5j^2+24j-5=0

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Solution for 5j^2+24j-5=0 equation:


Simplifying
5j2 + 24j + -5 = 0

Reorder the terms:
-5 + 24j + 5j2 = 0

Solving
-5 + 24j + 5j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-5 + -1j)(1 + -5j) = 0

Subproblem 1

Set the factor '(-5 + -1j)' equal to zero and attempt to solve: Simplifying -5 + -1j = 0 Solving -5 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1j = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1j = 0 + 5 -1j = 0 + 5 Combine like terms: 0 + 5 = 5 -1j = 5 Divide each side by '-1'. j = -5 Simplifying j = -5

Subproblem 2

Set the factor '(1 + -5j)' equal to zero and attempt to solve: Simplifying 1 + -5j = 0 Solving 1 + -5j = 0 Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5j = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5j = 0 + -1 -5j = 0 + -1 Combine like terms: 0 + -1 = -1 -5j = -1 Divide each side by '-5'. j = 0.2 Simplifying j = 0.2

Solution

j = {-5, 0.2}

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